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前些天朋友公司的考试题,他们跟我说了,我没事做了做。简单的实现了一下。里面有的英文单词不对,不想改了,呵呵,反正就是这个意思。代码写的有点冗余,但功能还是实现了。不过只做了四位数的。
namespace CountNum
{
class Program
{
static void Main(string[] args)
{
Dictionary
Dictionary
Dictionary
//读取数字文本
string[] textNums = File.ReadAllLines("1.txt", Encoding.UTF8);
string[] saveTestEnglish = new string[textNums.Length];
for (int i = 0; i < textNums.Length; i++)
{
Match match = Regex.Match(textNums[i], @"\d[1-9]");
//int number = int.Parse(textNums[i]);
string number = textNums[i];
if (match.Success)
{
switch (number.Length)
{
case 1:
//个位数的英文读入
int ge = int.Parse(number);
saveTestEnglish[i] = dicGeEnglishGeWei[ge];
break;
case 2:
if (number[0] == '1')
{
int shi = int.Parse(number);
saveTestEnglish[i] = dicGetDuble[shi];
}
else
{
saveTestEnglish[i] = dicGetEnglishShiWei[SubS(number)] + dicGeEnglishGeWei[SubS((int.Parse(number) - 1).ToString())];
}
break;
case 3:
if (number[1] == '1')
{
saveTestEnglish[i] = dicGeEnglishGeWei[SubS(number)] + " hunred and" + dicGetDuble[int.Parse(number.Substring(1))];
}
else
{
saveTestEnglish[i] = dicGeEnglishGeWei[SubS(number)] + " hunred and" + dicGetEnglishShiWei[SubS(number.Substring(1))] + dicGeEnglishGeWei[SubS(number.Substring(2))];
}
break;
case 4:
if (number[2] == '1')
{
saveTestEnglish[i] = dicGeEnglishGeWei[SubS(number)] + " thousand " + dicGeEnglishGeWei[SubS(number.Substring(1))] + " hunred and" + dicGetDuble[int.Parse(number.Substring(2))];
}
else
{
saveTestEnglish[i] = dicGeEnglishGeWei[SubS(number)] + " thousand " + dicGeEnglishGeWei[SubS(number.Substring(1))] + " hunred and" + dicGetEnglishShiWei[SubS(number.Substring(2))] + dicGeEnglishGeWei[SubS(number.Substring(3))];
}
break;
default:
break;
}
}
else
{
saveTestEnglish[i] = "Error";
}
}
for (int j = 0; j < saveTestEnglish.Length; j++)
{
Console.WriteLine(saveTestEnglish[j]);
}
Console.Read();
}
///
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